If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1.3x^2-9x+10=0
a = 1.3; b = -9; c = +10;
Δ = b2-4ac
Δ = -92-4·1.3·10
Δ = 29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{29}}{2*1.3}=\frac{9-\sqrt{29}}{2.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{29}}{2*1.3}=\frac{9+\sqrt{29}}{2.6} $
| -p+10=p | | y+2(1)=3 | | 7x+12(x-9)+4(3x+6)=5(3x-2)+8(-3) | | 43=4x+15 | | 4x+1/3+2x-1/2=6+3x-7/5 | | 3x+2x+1=41 | | 5(2x-1)=3(3x+5) | | 16=x/6-1 | | -1=7(u-7)+5u | | 5f=3f+6 | | 7k-5=11 | | y-3=+4 | | 90+10x+8x=180 | | 1/4x^2+11=38 | | -15r-8=-11r | | 18=5y-2y | | 24=2(x+8)+6x | | 4x^2-x^2-1600=0 | | 13x^2-9x+10=0 | | (3x-1)(x+7)=(3x+2)(x+5) | | w/3-3.1=-10.6 | | 5(y-2)+8y=16 | | 3(4x+5)+7=-2(3x+23)-4 | | 5u-16=74 | | 4(3c+2)=56 | | 2^2-3x4=0 | | 8x+3/4=7x | | 3/e=6 | | 103=-x+206 | | 2x^2-3x4=0 | | g-10=10 | | E^(2x)=15 |